Semiconductor Devices
Telangana Open School (TOSS) · Class 12 · Physics
Flashcards for Semiconductor Devices — Telangana Open School (TOSS) Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.
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What is the resistivity range for semiconductors?
Answer
The resistivity of semiconductors lies between \(10^{-5} \, \Omega\mathrm{m}\) and \(10^{6} \, \Omega\mathrm{m}\). This is higher than metals but lower than insulators.
Differentiate between n-type and p-type semiconductors.
Answer
n-type semiconductor is formed by doping a pure semiconductor (like Si or Ge) with a pentavalent impurity (like P, As). It has electrons as majority carriers. p-type semiconductor is formed by doping …
Calculate the conductivity of a semiconductor if its resistivity is \(2 imes 10^3 \, \Omega\mathrm{m}\).
Answer
Conductivity \( \sigma = rac{1}{ ho} \) Step 1: \( ho = 2 imes 10^3 \, \Omega\mathrm{m} \) Step 2: \( \sigma = rac{1}{2 imes 10^3} = 5 imes 10^{-4} \, \mathrm{S/m} \) Answer: \( 5 imes 10^{-4} …
Explain the formation of the depletion region in a p-n junction.
Answer
When a p-type and n-type semiconductor are joined, electrons from the n-side diffuse into the p-side and recombine with holes. This creates a narrow region near the junction depleted of mobile charge …
What is the barrier potential for silicon and germanium p-n junctions?
Answer
The barrier potential is approximately 0.7 V for silicon and 0.3 V for germanium at room temperature. This potential opposes the diffusion of majority carriers across the junction.
A p-n junction diode has a knee voltage of 0.7 V. If the applied forward voltage is 0.5 V, will it conduct? Why?
Answer
No, the diode will not conduct significantly. The applied voltage (0.5 V) is less than the knee voltage (0.7 V), so it cannot overcome the barrier potential. Hence, very little current flows.
In a forward-biased p-n junction, what happens to the width of the depletion region?
Answer
The width of the depletion region decreases. Forward bias reduces the potential barrier, allowing majority carriers to cross the junction more easily, thus reducing the space-charge region.
What is the reverse saturation current in a p-n junction diode?
Answer
It is the small current that flows under reverse bias due to minority carriers (electrons in p-region and holes in n-region). It is nearly constant and independent of reverse voltage until breakdown.
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