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Thermal Properties of Matter

Telangana Open School (TOSS) · Class 12 · Physics

Flashcards for Thermal Properties of Matter — Telangana Open School (TOSS) Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

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Card 1Conduction

What is the rate of heat conduction through a copper slab of thickness 0.02 m and area 0.5 m², if one face is at 100°C and the other at 30°C? (K for copper = 400 Wm⁻¹K⁻¹)

Answer

Given: K = 400 Wm⁻¹K⁻¹, A = 0.5 m², d = 0.02 m, ΔT = 100 – 30 = 70°C, t = 1 s Using formula: Q = KA(ΔT)t / d Step 1: Q = (400)(0.5)(70)(1) / 0.02 Step 2: Q = 14000 / 0.02 = 700,000 J Answer: 700,000 J

Card 2Conduction

How much heat is transferred in 10 minutes through a glass window of area 2 m² and thickness 0.5 cm when the inside temperature is 25°C and outside is 5°C? (K_glass = 0.8 Wm⁻¹K⁻¹)

Answer

Given: K = 0.8, A = 2 m², d = 0.005 m, ΔT = 20°C, t = 10×60 = 600 s Formula: Q = KA(ΔT)t / d Step 1: Q = (0.8)(2)(20)(600) / 0.005 Step 2: Q = 19200 / 0.005 = 3,840,000 J Answer: 3.84 × 10⁶ J

Card 3Conduction

A thermocol box has wall thickness 4 cm and surface area 0.8 m². If the temperature difference is 40°C, how much heat enters the box in 1 hour? (K = 0.01 Wm⁻¹K⁻¹)

Answer

Given: K = 0.01, A = 0.8 m², d = 0.04 m, ΔT = 40°C, t = 3600 s Q = KA(ΔT)t / d Step 1: Q = (0.01)(0.8)(40)(3600) / 0.04 Step 2: Q = 11520 / 0.04 = 288,000 J Answer: 288 kJ

Card 4Conduction

An aluminum rod of cross-section 0.03 m² and length 0.6 m conducts 5000 J of heat in 1 minute. Find the temperature difference across the rod. (K_Al = 240 Wm⁻¹K⁻¹)

Answer

Given: Q = 5000 J, t = 60 s, K = 240, A = 0.03 m², d = 0.6 m From Q = KA(ΔT)t / d → ΔT = Qd / (KAt) Step 1: ΔT = (5000)(0.6) / (240 × 0.03 × 60) Step 2: ΔT = 3000 / 432 = 6.94 K Answer: 6.94°C

Card 5Conduction

A slab of concrete (K = 1.2 Wm⁻¹K⁻¹) has area 3 m² and thickness 10 cm. If it loses 5.4 × 10⁵ J of heat in 2 hours, find the temperature difference between its faces.

Answer

Given: Q = 5.4×10⁵ J, t = 7200 s, K = 1.2, A = 3 m², d = 0.1 m ΔT = Qd / (KAt) Step 1: ΔT = (5.4×10⁵)(0.1) / (1.2 × 3 × 7200) Step 2: ΔT = 54000 / 25920 = 2.08 K Answer: 2.08°C

Card 6Conduction

Why does a metal spoon feel colder than a wooden spoon at room temperature?

Answer

Metal is a good conductor of heat (high thermal conductivity), so it quickly draws heat from your hand, making it feel cold. Wood is a poor conductor (insulator), so it doesn't draw heat as fast, feel

Card 7Conduction

Explain why cooking pots are made of copper or aluminum.

Answer

Copper and aluminum have high thermal conductivity (400 and 240 Wm⁻¹K⁻¹ respectively), allowing heat to spread quickly and evenly across the pot. This ensures uniform cooking and faster heating.

Card 8Conduction

Why do we wear woolen clothes in winter?

Answer

Wool traps air between its fibers. Air is a poor conductor of heat (low K), so it reduces heat loss from the body. This insulation keeps us warm in cold weather.

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What are the important topics in Thermal Properties of Matter for Telangana Open School (TOSS) Class 12 Physics?
Thermal Properties of Matter covers several key topics that are frequently asked in Telangana Open School (TOSS) Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
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