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Mechanical Properties of Fluids

Telangana Open School (TOSS) · Class 12 · Physics

Flashcards for Mechanical Properties of Fluids — Telangana Open School (TOSS) Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

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28 Flashcards
Card 1Hydrostatic Pressure

State the formula for hydrostatic pressure at a depth h in a liquid of density ρ.

Answer

Hydrostatic pressure is given by: $$ P = P_{\text{atm}} + \rho g h $$ Where: - $ P $ = absolute pressure at depth $ h $ - $ P_{\text{atm}} $ = atmospheric pressure ($ 1.01 \times 10^5 \, \text{Pa}

Card 2Hydrostatic Pressure

Calculate the pressure at the bottom of a 1500 m deep ocean. Density of seawater = $1.024 \times 10^3 \, \text{kg/m}^3$, $g = 9.80 \, \text{m/s}^2$, $P_{\text{atm}} = 1.01 \times 10^5 \, \text{Pa}$.

Answer

Given: - $ h = 1500 \, \text{m} $ - $ \rho = 1024 \, \text{kg/m}^3 $ - $ g = 9.80 \, \text{m/s}^2 $ - $ P_{\text{atm}} = 1.01 \times 10^5 \, \text{Pa} $ Formula: $ P = P_{\text{atm}} + \rho g h $ St

Card 3Hydrostatic Pressure

Why are dam walls thicker at the bottom?

Answer

Because hydrostatic pressure increases linearly with depth ($ P \propto h $). The deeper the water, the greater the pressure exerted on the dam wall. To withstand this increasing pressure, the wall mu

Card 4Pascal's Law

What is Pascal's Law?

Answer

Pascal's Law states that when pressure is applied to an enclosed fluid, it is transmitted undiminished to every part of the fluid and to the walls of the container. This means that a small force appl

Card 5Pascal's Law

In a hydraulic lift, a force of 500 N is applied on a piston of area 0.02 m². What force is exerted on a second piston of area 1.5 m²?

Answer

Given: - $ F_1 = 500 \, \text{N} $ - $ A_1 = 0.02 \, \text{m}^2 $ - $ A_2 = 1.5 \, \text{m}^2 $ By Pascal’s Law: $ \frac{F_1}{A_1} = \frac{F_2}{A_2} $ Step 1: $ \frac{500}{0.02} = \frac{F_2}{1.5} $

Card 6Pascal's Law

Can a 25 kg boy lift a 5000 kg elephant using a hydraulic lift? The boy stands on a piston of area 0.05 m² and the elephant on one of 10 m².

Answer

Given: - $ m_1 = 25 \, \text{kg} \Rightarrow F_1 = 25 \times 9.8 = 245 \, \text{N} $ - $ A_1 = 0.05 \, \text{m}^2 $ - $ A_2 = 10 \, \text{m}^2 $ Using Pascal’s Law: $ \frac{F_1}{A_1} = \frac{F_2}{A_2

Card 7Surface Tension

Define surface tension.

Answer

Surface tension is the property of a liquid's surface that allows it to resist external force. It is defined as the force per unit length acting perpendicular to an imaginary line on the surface. $$

Card 8Surface Tension

Why do small drops of liquid form spheres?

Answer

Due to surface tension. A sphere has the smallest surface area for a given volume. The liquid surface tends to minimize its area due to cohesive forces between molecules, resulting in a spherical shap

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What are the important topics in Mechanical Properties of Fluids for Telangana Open School (TOSS) Class 12 Physics?
Mechanical Properties of Fluids covers several key topics that are frequently asked in Telangana Open School (TOSS) Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Mechanical Properties of Fluids — Telangana Open School (TOSS) Class 12 Physics?
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