Nuclear Physics
Telangana Open School (TOSS) · Class 12 · Physics
Flashcards for Nuclear Physics — Telangana Open School (TOSS) Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.
Interactive on Super Tutor
Studying Nuclear Physics? Get the full interactive chapter.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for flashcards and more.
1,000+ Class 12 students started this chapter today
What is the atomic number (Z) and mass number (A) of an atom?
Answer
Atomic number (Z) is the number of protons in the nucleus. Mass number (A) is the total number of protons and neutrons (nucleons) in the nucleus. For example, in \( {}_{92}^{238}\mathrm{U} \), Z = 92 …
Define isotopes, isobars, and isotones with examples.
Answer
Isotopes: Atoms of same element (same Z) but different mass numbers (A). Example: \( {}_{6}^{12}\mathrm{C} \) and \( {}_{6}^{14}\mathrm{C} \). Isobars: Atoms with same A but different Z. Example: \( {…
Calculate the number of neutrons in \( {}_{13}^{27}\mathrm{Al} \) and \( {}_{14}^{28}\mathrm{Si} \).
Answer
Number of neutrons = A – Z. For \( {}_{13}^{27}\mathrm{Al} \): N = 27 – 13 = 14. For \( {}_{14}^{28}\mathrm{Si} \): N = 28 – 14 = 14. So both have 14 neutrons.
What is the approximate radius of a nucleus with mass number A?
Answer
The radius R of a nucleus is given by: \( R = r_0 A^{1/3} \), where \( r_0 = 1.2 imes 10^{-15} \, ext{m} \) (1.2 fm). For example, for A = 8, \( R = 1.2 imes 8^{1/3} = 1.2 imes 2 = 2.4 \, ext{fm}…
Find the radius of the nucleus of \( {}_{4}^{8}\mathrm{Be} \).
Answer
Given: \( R = r_0 A^{1/3} \), \( r_0 = 1.2 imes 10^{-15} \, ext{m} \), A = 8. Step 1: \( A^{1/3} = 8^{1/3} = 2 \). Step 2: \( R = 1.2 imes 10^{-15} imes 2 = 2.4 imes 10^{-15} \, ext{m} \). Answe…
What is unified atomic mass unit (u)? How is it related to MeV?
Answer
1 u = 1/12th the mass of a \( {}_{6}^{12}\mathrm{C} \) atom = \( 1.660565 imes 10^{-27} \, ext{kg} \). Using \( E = mc^2 \), 1 u = 931.3 MeV. This is used to express nuclear masses and calculate bin…
Define mass defect and write its formula.
Answer
Mass defect (\( \Delta m \)) is the difference between the sum of masses of individual nucleons and the actual mass of the nucleus. Formula: \( \Delta m = [Z m_p + (A-Z) m_n] - M \), where M is the ac…
Calculate the binding energy per nucleon for \( {}_{3}^{7}\mathrm{Li} \) if its nuclear mass is 6.01513 u.
Answer
Given: \( m_p = 1.00727 \, ext{u} \), \( m_n = 1.00865 \, ext{u} \), A = 7, Z = 3. Step 1: Sum of nucleon masses = \( 3(1.00727) + 4(1.00865) = 3.02181 + 4.0346 = 7.05641 \, ext{u} \). Step 2: Mass…
+22 more flashcards available
Practice AllFrequently Asked Questions
What are the important topics in Nuclear Physics for Telangana Open School (TOSS) Class 12 Physics?
How to score full marks in Nuclear Physics — Telangana Open School (TOSS) Class 12 Physics?
How many flashcards are available for Nuclear Physics?
Sources & Official References
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
More resources for Nuclear Physics
Practice Quiz
Test yourself with a quick quiz
Important Questions
Practice with board exam-style questions
Revision Notes
Key points for last-minute revision
Formula Sheet
All formulas in one place
Chapter Summary
Understand the chapter at a glance
Concept Maps
See how topics connect visually
Study Plan
Step-by-step plan to ace this chapter
Syllabus
What topics to cover
NCERT Solutions
Every textbook question solved step by step
For serious students
Get the full Nuclear Physics chapter — for free.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan for Telangana Open School (TOSS) Class 12 Physics.