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Nuclear Physics

Telangana Open School (TOSS) · Class 12 · Physics

Flashcards for Nuclear Physics — Telangana Open School (TOSS) Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

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Card 1Atomic Nucleus

What is the atomic number (Z) and mass number (A) of an atom?

Answer

Atomic number (Z) is the number of protons in the nucleus. Mass number (A) is the total number of protons and neutrons (nucleons) in the nucleus. For example, in \( {}_{92}^{238}\mathrm{U} \), Z = 92

Card 2Atomic Nucleus

Define isotopes, isobars, and isotones with examples.

Answer

Isotopes: Atoms of same element (same Z) but different mass numbers (A). Example: \( {}_{6}^{12}\mathrm{C} \) and \( {}_{6}^{14}\mathrm{C} \). Isobars: Atoms with same A but different Z. Example: \( {

Card 3Atomic Nucleus

Calculate the number of neutrons in \( {}_{13}^{27}\mathrm{Al} \) and \( {}_{14}^{28}\mathrm{Si} \).

Answer

Number of neutrons = A – Z. For \( {}_{13}^{27}\mathrm{Al} \): N = 27 – 13 = 14. For \( {}_{14}^{28}\mathrm{Si} \): N = 28 – 14 = 14. So both have 14 neutrons.

Card 4Size of Nucleus

What is the approximate radius of a nucleus with mass number A?

Answer

The radius R of a nucleus is given by: \( R = r_0 A^{1/3} \), where \( r_0 = 1.2 imes 10^{-15} \, ext{m} \) (1.2 fm). For example, for A = 8, \( R = 1.2 imes 8^{1/3} = 1.2 imes 2 = 2.4 \, ext{fm}

Card 5Size of Nucleus

Find the radius of the nucleus of \( {}_{4}^{8}\mathrm{Be} \).

Answer

Given: \( R = r_0 A^{1/3} \), \( r_0 = 1.2 imes 10^{-15} \, ext{m} \), A = 8. Step 1: \( A^{1/3} = 8^{1/3} = 2 \). Step 2: \( R = 1.2 imes 10^{-15} imes 2 = 2.4 imes 10^{-15} \, ext{m} \). Answe

Card 6Atomic Mass

What is unified atomic mass unit (u)? How is it related to MeV?

Answer

1 u = 1/12th the mass of a \( {}_{6}^{12}\mathrm{C} \) atom = \( 1.660565 imes 10^{-27} \, ext{kg} \). Using \( E = mc^2 \), 1 u = 931.3 MeV. This is used to express nuclear masses and calculate bin

Card 7Mass Defect and Binding Energy

Define mass defect and write its formula.

Answer

Mass defect (\( \Delta m \)) is the difference between the sum of masses of individual nucleons and the actual mass of the nucleus. Formula: \( \Delta m = [Z m_p + (A-Z) m_n] - M \), where M is the ac

Card 8Mass Defect and Binding Energy

Calculate the binding energy per nucleon for \( {}_{3}^{7}\mathrm{Li} \) if its nuclear mass is 6.01513 u.

Answer

Given: \( m_p = 1.00727 \, ext{u} \), \( m_n = 1.00865 \, ext{u} \), A = 7, Z = 3. Step 1: Sum of nucleon masses = \( 3(1.00727) + 4(1.00865) = 3.02181 + 4.0346 = 7.05641 \, ext{u} \). Step 2: Mass

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What are the important topics in Nuclear Physics for Telangana Open School (TOSS) Class 12 Physics?
Nuclear Physics covers several key topics that are frequently asked in Telangana Open School (TOSS) Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Nuclear Physics — Telangana Open School (TOSS) Class 12 Physics?
Understand the core concepts first, then work through the 53 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
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There are 30 flashcards for Nuclear Physics covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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