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Current Electricity

Telangana Open School (TOSS) · Class 12 · Physics

Flashcards for Current Electricity — Telangana Open School (TOSS) Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

43 questions30 flashcards5 concepts

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30 Flashcards
Card 1Ohm's Law

State Ohm's Law.

Answer

Ohm's Law states that the current (I) flowing through a conductor is directly proportional to the potential difference (V) across its ends, provided the physical conditions like temperature and pressu

Card 2Ohm's Law

A current of 2 A flows through a wire when a potential difference of 10 V is applied. Find the resistance.

Answer

Given: V = 10 V, I = 2 A Using Ohm’s Law: R = V / I Step 1: R = 10 V / 2 A = 5 Ω Answer: 5 Ω

Card 3Electric Current

Why does a bulb glow as soon as you switch on the circuit?

Answer

When the switch is turned on, an electric field is established almost instantly throughout the circuit. This field exerts a force on free electrons in the conductor, causing them to drift and produce

Card 4Electric Current

Define electric current and give its SI unit.

Answer

Electric current is the rate of flow of electric charge through a cross-sectional area of a conductor. Mathematically, I = Δq / Δt, where Δq is the net charge passing through the area in time Δt. The

Card 5Electric Current

Calculate the current if 3 × 10¹⁸ electrons pass through a wire in 2 seconds.

Answer

Given: Number of electrons = 3 × 10¹⁸, t = 2 s Charge of one electron = 1.6 × 10⁻¹⁹ C Total charge: q = (3 × 10¹⁸) × (1.6 × 10⁻¹⁹) = 0.48 C Current: I = q / t = 0.48 C / 2 s = 0.24 A Answer: 0.24 A

Card 6Resistance and Resistivity

What is resistivity? How is it different from resistance?

Answer

Resistivity (ρ) is an intrinsic property of a material that measures how strongly it opposes the flow of electric current. It depends only on the nature and temperature of the material, not on its dim

Card 7Resistance and Resistivity

A copper wire has length 2 m and cross-sectional area 2 × 10⁻⁶ m². If resistivity of copper is 1.7 × 10⁻⁸ Ω·m, find its resistance.

Answer

Given: L = 2 m, A = 2 × 10⁻⁶ m², ρ = 1.7 × 10⁻⁸ Ω·m Formula: R = ρL / A Step 1: R = (1.7 × 10⁻⁸) × (2) / (2 × 10⁻⁶) Step 2: R = (3.4 × 10⁻⁸) / (2 × 10⁻⁶) = 1.7 × 10⁻² Ω Answer: 0.017 Ω

Card 8Resistance and Resistivity

Two wires of same material have lengths in ratio 1:2 and radii in ratio 2:1. Compare their resistances.

Answer

Let wire 1: L₁ = L, r₁ = 2r → A₁ = π(2r)² = 4πr² Wire 2: L₂ = 2L, r₂ = r → A₂ = πr² R ∝ L / A So, R₁/R₂ = (L₁/L₂) × (A₂/A₁) = (1/2) × (πr² / 4πr²) = (1/2) × (1/4) = 1/8 Therefore, R₁ : R₂ = 1 : 8

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What are the important topics in Current Electricity for Telangana Open School (TOSS) Class 12 Physics?
Current Electricity covers several key topics that are frequently asked in Telangana Open School (TOSS) Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Current Electricity — Telangana Open School (TOSS) Class 12 Physics?
Understand the core concepts first, then work through the 43 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
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There are 30 flashcards for Current Electricity covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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