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Aldehydes, Ketones and Carboxylic Acids

Telangana Open School (TOSS) · Class 12 · Chemistry

Flashcards for Aldehydes, Ketones and Carboxylic Acids — Telangana Open School (TOSS) Class 12 Chemistry. Quick Q&A cards covering key concepts, definitions, and formulas.

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Card 1Nomenclature of Aldehydes

What is the IUPAC name of CH₃CHO?

Answer

The IUPAC name of CH₃CHO is Ethanal. The compound has a two-carbon chain with an aldehyde group (-CHO), so it is named by replacing the '-e' of ethane with '-al'.

Card 2Nomenclature of Ketones

What is the IUPAC name of CH₃COCH₃?

Answer

The IUPAC name of CH₃COCH₃ is Propanone. It has a three-carbon chain with a ketone group at carbon 2, so it is named by replacing the '-e' of propane with '-one'.

Card 3Aromatic Aldehydes

Give the structure and IUPAC name of benzaldehyde.

Answer

Benzaldehyde has a benzene ring attached to a -CHO group. Its IUPAC name is Benzenecarbaldehyde. Structure: C₆H₅CHO.

Card 4Reactivity of Carbonyl Compounds

Why are aldehydes more reactive than ketones in nucleophilic addition reactions?

Answer

Aldehydes are more reactive because: (1) They have only one electron-donating alkyl group, making the carbonyl carbon more electrophilic. (2) The carbonyl carbon in aldehydes is less sterically hinder

Card 5Nucleophilic Addition Reactions

Explain the formation of cyanohydrin from acetaldehyde.

Answer

Acetaldehyde reacts with HCN to form 2-hydroxypropanenitrile (cyanohydrin): CH₃CHO + HCN → CH₃CH(OH)CN This is a nucleophilic addition reaction where CN⁻ attacks the electrophilic carbonyl carbon.

Card 6Formation of Hemiacetals and Acetals

What happens when ethanal reacts with methanol in the presence of dry HCl?

Answer

Ethanal forms first a hemiacetal and then an acetal: CH₃CHO + CH₃OH → CH₃CH(OH)OCH₃ (hemiacetal) CH₃CH(OH)OCH₃ + CH₃OH → CH₃CH(OCH₃)₂ + H₂O (acetal) This reaction is acid-catalyzed and reversible.

Card 7Reaction with Ammonia

How does formaldehyde react with ammonia?

Answer

Formaldehyde reacts with ammonia to form hexamethylenetetramine (urotropine): 6HCHO + 4NH₃ → (CH₂)₆N₄ + 6H₂O This is a condensation reaction used in medicine and as a urinary antiseptic.

Card 8Aldol Condensation

What is the product when propanal undergoes aldol condensation?

Answer

Propanal undergoes aldol condensation in dilute NaOH to form 3-hydroxy-2-methylpentanal, which on heating gives 2-methylpent-2-enal: 2CH₃CH₂CHO → CH₃CH₂CH(OH)CH(CH₃)CHO → CH₃CH₂C(=CHCH₃)CHO + H₂O Th

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