Spontaneity of Chemical reactions
Telangana Open School (TOSS) · Class 12 · Chemistry
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What is a spontaneous process? Give one example.
Answer
A spontaneous process occurs naturally without external help once started. Example: Rusting of iron — iron reacts with oxygen and moisture to form rust (Fe₂O₃) without any continuous external input.
Why is the cooling of hot water a spontaneous process?
Answer
Hot water loses heat to the cooler surroundings until thermal equilibrium is reached. This happens naturally due to temperature difference, so it’s spontaneous. The reverse (water heating up by absorb…
Define entropy (S). How is it related to disorder?
Answer
Entropy (S) is a thermodynamic property that measures the degree of randomness or disorder in a system. Higher disorder means higher entropy. For example, gases have more entropy than liquids, which h…
Arrange the following in order of increasing entropy: 1 mol H₂O(s), 1 mol H₂O(l), 1 mol H₂O(g)
Answer
H₂O(s) < H₂O(l) < H₂O(g). Solid water (ice) is most ordered (lowest entropy), liquid has moderate disorder, and gas has maximum randomness (highest entropy).
What is the formula for entropy change during a reversible process?
Answer
The entropy change is given by: $$ \Delta S = \frac{q_{\text{rev}}}{T} $$ where $ q_{\text{rev}} $ is the heat transferred reversibly and $ T $ is the absolute temperature in Kelvin.
Calculate the entropy change when 1 mol of ice melts at 273 K. $\Delta_{\text{fus}}H = 6.02\,\mathrm{kJ\,mol^{-1}}$
Answer
Given: - $\Delta_{\text{fus}}H = 6.02\,\mathrm{kJ\,mol^{-1}} = 6020\,\mathrm{J\,mol^{-1}}$ - $T = 273\,\mathrm{K}$ $$ \Delta_{\text{fus}}S = \frac{\Delta_{\text{fus}}H}{T} = \frac{6020}{273} = 22.05\…
Calculate the entropy change for vaporization of water at 373 K if $\Delta_{\text{vap}}H = 40.8\,\mathrm{kJ\,mol^{-1}}$
Answer
Given: - $\Delta_{\text{vap}}H = 40.8\,\mathrm{kJ\,mol^{-1}} = 40800\,\mathrm{J\,mol^{-1}}$ - $T = 373\,\mathrm{K}$ $$ \Delta_{\text{vap}}S = \frac{\Delta_{\text{vap}}H}{T} = \frac{40800}{373} = 109.
What does the second law of thermodynamics say about spontaneous processes?
Answer
The second law states that for any spontaneous process, the total entropy of the universe increases: $$ \Delta S_{\text{univ}} = \Delta S_{\text{sys}} + \Delta S_{\text{surr}} > 0 $$ At equilibrium, $…
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