Chemical Arithmetics — Flashcards
Telangana Open School (TOSS) · Class 12 · Chemistry
30 flashcards for Chemical Arithmetics (Telangana Open School (TOSS) Class 12 Chemistry) to test yourself on key terms and facts.
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Define empirical formula.
Answer
Empirical formula is the simplest whole-number ratio of atoms of each element in a compound. It does not show the actual number of atoms but gives the relative proportions. For example, the empirical …
Define molecular formula.
Answer
Molecular formula shows the actual number of atoms of each element in a molecule. It is a whole-number multiple of the empirical formula. For example, benzene has molecular formula C₆H₆ and empirical …
What is the relationship between molecular formula and empirical formula?
Answer
Molecular formula = n × Empirical formula, where n is a positive integer. For example, acetic acid has molecular formula C₂H₄O₂ and empirical formula CH₂O, so n = 2.
Why do ionic compounds like NaCl not have molecular formulas?
Answer
Ionic compounds exist as crystal lattices made of repeating ions, not discrete molecules. Therefore, they are represented by empirical formulas showing the simplest ion ratio. NaCl means Na⁺ and Cl⁻ i…
Calculate the percentage of carbon in methane (CH₄).
Answer
Molar mass of CH₄ = 12 + 4×1 = 16 g/mol Mass of C = 12 g % C = (12 / 16) × 100 = 75% Answer: 75%…
Find the percentage of oxygen in water (H₂O).
Answer
Molar mass of H₂O = 2×1 + 16 = 18 g/mol Mass of O = 16 g % O = (16 / 18) × 100 = 88.89% Answer: 88.89%…
A compound contains 40% carbon, 6.67% hydrogen, and 53.33% oxygen. Find its empirical formula.
Answer
Assume 100 g sample: C: 40 g → 40/12 = 3.33 mol H: 6.67 g → 6.67/1 = 6.67 mol O: 53.33 g → 53.33/16 = 3.33 mol Divide by smallest (3.33): C: 1, H: 2, O: 1 Empirical formula: CH₂O…
A compound has 52.9% aluminum and 47.1% oxygen. Find its empirical formula.
Answer
Assume 100 g sample: Al: 52.9 g → 52.9/27 = 1.96 mol O: 47.1 g → 47.1/16 = 2.94 mol Divide by smallest (1.96): Al: 1, O: 1.5 → Multiply by 2: Al₂O₃ Empirical formula: Al₂O₃…
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