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Chemical Arithmetics

Telangana Open School (TOSS) · Class 12 · Chemistry

Flashcards for Chemical Arithmetics — Telangana Open School (TOSS) Class 12 Chemistry. Quick Q&A cards covering key concepts, definitions, and formulas.

53 questions30 flashcards4 concepts

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Card 1Empirical and Molecular Formulae

Define empirical formula.

Answer

Empirical formula is the simplest whole-number ratio of atoms of each element in a compound. It does not show the actual number of atoms but gives the relative proportions. For example, the empirical

Card 2Empirical and Molecular Formulae

Define molecular formula.

Answer

Molecular formula shows the actual number of atoms of each element in a molecule. It is a whole-number multiple of the empirical formula. For example, benzene has molecular formula C₆H₆ and empirical

Card 3Empirical and Molecular Formulae

What is the relationship between molecular formula and empirical formula?

Answer

Molecular formula = n × Empirical formula, where n is a positive integer. For example, acetic acid has molecular formula C₂H₄O₂ and empirical formula CH₂O, so n = 2.

Card 4Empirical and Molecular Formulae

Why do ionic compounds like NaCl not have molecular formulas?

Answer

Ionic compounds exist as crystal lattices made of repeating ions, not discrete molecules. Therefore, they are represented by empirical formulas showing the simplest ion ratio. NaCl means Na⁺ and Cl⁻ i

Card 5Percentage Composition

Calculate the percentage of carbon in methane (CH₄).

Answer

Molar mass of CH₄ = 12 + 4×1 = 16 g/mol Mass of C = 12 g % C = (12 / 16) × 100 = 75% Answer: 75%

Card 6Percentage Composition

Find the percentage of oxygen in water (H₂O).

Answer

Molar mass of H₂O = 2×1 + 16 = 18 g/mol Mass of O = 16 g % O = (16 / 18) × 100 = 88.89% Answer: 88.89%

Card 7Empirical Formula Determination

A compound contains 40% carbon, 6.67% hydrogen, and 53.33% oxygen. Find its empirical formula.

Answer

Assume 100 g sample: C: 40 g → 40/12 = 3.33 mol H: 6.67 g → 6.67/1 = 6.67 mol O: 53.33 g → 53.33/16 = 3.33 mol Divide by smallest (3.33): C: 1, H: 2, O: 1 Empirical formula: CH₂O

Card 8Empirical Formula Determination

A compound has 52.9% aluminum and 47.1% oxygen. Find its empirical formula.

Answer

Assume 100 g sample: Al: 52.9 g → 52.9/27 = 1.96 mol O: 47.1 g → 47.1/16 = 2.94 mol Divide by smallest (1.96): Al: 1, O: 1.5 → Multiply by 2: Al₂O₃ Empirical formula: Al₂O₃

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Frequently Asked Questions

What are the important topics in Chemical Arithmetics for Telangana Open School (TOSS) Class 12 Chemistry?
Chemical Arithmetics covers several key topics that are frequently asked in Telangana Open School (TOSS) Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Chemical Arithmetics — Telangana Open School (TOSS) Class 12 Chemistry?
Understand the core concepts first, then work through the 53 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Chemical Arithmetics?
There are 30 flashcards for Chemical Arithmetics covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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