Dispersion and Scattering of Light
NIOS · Class 12 · Physics
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What is dispersion of light? How is it different from refraction?
Answer
Dispersion is the splitting of white light into its constituent colours (wavelengths) when it passes through a dispersive medium like a prism. Key Difference: • Refraction = bending of light at an in…
State the relationship between refractive index (μ) and wavelength of light. Which colour has the highest and lowest refractive index in glass?
Answer
Key Formula: μ = c/v = λ_air / λ_medium Where: • c = speed of light in vacuum = 3 × 10⁸ m/s • v = speed of light in the medium • λ_air = wavelength in air, λ_medium = wavelength in the medium Relati…
NUMERICAL: A beam of light of average wavelength 600 nm enters a glass prism and splits into wavelengths 384 nm and 760 nm inside the prism. Calculate the refractive index for each wavelength.
Answer
Given: • λ_air (average incident) = 600 nm • λ_medium1 = 384 nm (inside prism) • λ_medium2 = 760 nm (inside prism) Formula: μ = λ_air / λ_medium Step 1 – For 384 nm: μ₁ = 600 nm / 384 nm = 1.5625 ≈ …
Derive the relation: δ = (i + e) − A for a prism, where δ = angle of deviation, i = angle of incidence, e = angle of emergence, A = angle of prism.
Answer
Setup: • Light PQ hits face AB of prism ABC at point Q • Refracts inside as QR, exits from face AC as RS • r₁ = angle of refraction at AB, r₂ = angle of refraction at AC Step 1 – Angle of deviation δ…
What is the angle of minimum deviation (δₘ)? What special condition holds at minimum deviation?
Answer
Angle of Minimum Deviation (δₘ): As the angle of incidence i increases, the angle of deviation δ first decreases, reaches a minimum value δₘ, then increases again. Special condition at minimum deviat…
State and derive the formula for refractive index of a prism material in terms of angle of minimum deviation (δₘ) and angle of prism (A).
Answer
Formula: μ = sin[(A + δₘ)/2] / sin(A/2) Derivation: At minimum deviation condition: • i = (A + δₘ)/2 [from i + e = A + δₘ and i = e] • r = A/2 [from r₁ + r₂ = A and r₁ = r₂] Applying Snell's law a…
NUMERICAL: A 60° glass prism has an angle of minimum deviation of 39°. Calculate the refractive index of glass.
Answer
Given: • A = 60° • δₘ = 39° Formula: μ = sin[(A + δₘ)/2] / sin(A/2) Step 1 – Calculate numerator: (A + δₘ)/2 = (60° + 39°)/2 = 99°/2 = 49.5° sin(49.5°) = 0.760 Step 2 – Calculate denominator: A/2 =…
NUMERICAL: For a prism of angle A = 60°, the angle of minimum deviation is δₘ = A/2 = 30°. Calculate the refractive index.
Answer
Given: • A = 60° • δₘ = A/2 = 30° Formula: μ = sin[(A + δₘ)/2] / sin(A/2) Step 1: (A + δₘ)/2 = (60° + 30°)/2 = 90°/2 = 45° sin(45°) = 1/√2 = 0.7071 Step 2: A/2 = 30° sin(30°) = 0.5 Step 3: μ = (1/…
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