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Electric Charge and Electric Field

NIOS · Class 12 · Physics

Flashcards for Electric Charge and Electric Field — NIOS Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

43 questions34 flashcards5 concepts

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34 Flashcards
Card 1Coulomb's Law

State Coulomb's Law of electrostatics. Give the mathematical expression.

Answer

Coulomb's Law states that the electrostatic force between two stationary point charges is: • Directly proportional to the product of the charges (q₁ × q₂) • Inversely proportional to the square of the

Card 2Coulomb's Law

Two charges, each of 6.0 × 10⁻¹⁰ C, are separated by a distance of 2.0 m. Calculate the magnitude of the Coulomb force between them.

Answer

GIVEN: q₁ = q₂ = 6.0 × 10⁻¹⁰ C r = 2.0 m k = 9 × 10⁹ N·m²/C² FIND: F = ? FORMULA: F = k × q₁ × q₂ / r² SOLUTION: F = (9 × 10⁹) × (6.0 × 10⁻¹⁰) × (6.0 × 10⁻¹⁰) / (2.0)² F = (9 × 10⁹) × (36 × 10⁻²⁰)

Card 3Coulomb's Law

What is the Principle of Superposition of electric forces? How is the net force on a charge calculated when multiple charges are present?

Answer

Principle of Superposition states that the total electrostatic force on a charge q₁ due to multiple other charges is the VECTOR SUM of all individual forces. If charges q₂, q₃, q₄ exert forces F₁₂, F

Card 4Coulomb's Law

A charge +q₁ = 12 C is placed 4.0 m from +q₂ = 6 C. Where should a charge q₃ be placed on the line joining them so that q₃ experiences zero net force?

Answer

GIVEN: q₁ = 12 C, q₂ = 6 C, separation = 4 m Let q₃ be placed at distance x from q₁ FORCE BALANCE CONDITION: F₃₁ = F₃₂ k × 12 × q₃ / x² = k × 6 × q₃ / (4 - x)² Simplifying: 12 / x² = 6 / (4 - x)² 2(

Card 5Electric Field

Define Electric Field. Write its mathematical expression, SI unit, and direction convention.

Answer

Electric Field (E) at a point is defined as the electrostatic force experienced by a unit positive test charge placed at that point. Formula: E = F / q₀ For a point charge q: E = k × q / r² (directi

Card 6Electric Field

The electric force at a point due to a charge q = 3.5 μC is 8.5 × 10⁻⁴ N. Calculate the electric field strength at that point.

Answer

GIVEN: F = 8.5 × 10⁻⁴ N q = 3.5 μC = 3.5 × 10⁻⁶ C FIND: E = ? FORMULA: E = F / q SOLUTION: E = (8.5 × 10⁻⁴ N) / (3.5 × 10⁻⁶ C) E = (8.5 / 3.5) × 10⁻⁴⁺⁶ E = 2.43 × 10² N/C ANSWER: E = 243 N/C Veri

Card 7Electric Field

Why must the test charge q₀ used to measure electric field be infinitesimally small?

Answer

The test charge q₀ must be infinitesimally small because: Problem with large test charge: • A large q₀ creates its own electric field, which redistributes charges on the source conductor • This redis

Card 8Electric Dipole

Define Electric Dipole and Dipole Moment. What are the SI units and direction of the dipole moment vector?

Answer

Electric Dipole: A system of two equal and opposite charges (+q and −q) separated by a small distance 2l. Example: Water molecule (H₂O) is a natural dipole. Dipole Moment (p): • Definition: Product

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What are the important topics in Electric Charge and Electric Field for NIOS Class 12 Physics?
Key topics in Electric Charge and Electric Field include Chapter Overview: Electric Charge and Electric Field, Complete Chapter Concept Hierarchy — Electric Charge and Electric Field, Correct vs Incorrect Thinking: Dipole in Electric Field. These are the concepts NIOS Class 12 examiners draw on most — study them first, then practise related questions.
How to score full marks in Electric Charge and Electric Field — NIOS Class 12 Physics?
Understand the core concepts first, then work through the 43 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
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There are 34 flashcards for Electric Charge and Electric Field covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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