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Chapter 12 of 30
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Heat Transfer and Solar Energy

NIOS · Class 12 · Physics

Flashcards for Heat Transfer and Solar Energy — NIOS Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions34 flashcards5 concepts

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A diagram illustrating heat transfer through conduction in a solid material, showing molecular vibrations transferring energy along the material.
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34 Flashcards
Card 1Modes of Heat Transfer

State the three modes of heat transfer. How do they differ from each other?

Answer

The three modes of heat transfer are: 1. CONDUCTION: Heat transfer through a material medium where molecules vibrate in their fixed positions and pass energy to neighbours. Common in solids. 2. CONVEC

Card 2Conduction

Write the formula for heat transferred by conduction. Define each term and state its SI unit.

Answer

Formula: Q = KA(T_h - T_c)t / d Where: • Q = Heat transferred (Joules, J) • K = Coefficient of thermal conductivity (W m⁻¹ K⁻¹) • A = Area of cross-section (m²) • T_h = Higher temperature (K or °C) •

Card 3Conduction

Define the coefficient of thermal conductivity (K). What are its SI units?

Answer

Definition: The coefficient of thermal conductivity K is defined as the amount of heat transferred in one second across a material of cross-sectional area 1 m² and thickness 1 m, when opposite faces a

Card 4Conduction

A steel slab of area 2 m², thickness 0.02 m, and K = 50 W m⁻¹ K⁻¹ has its faces at 100°C and 20°C. Find the heat conducted in 5 minutes.

Answer

Given: • A = 2 m² • d = 0.02 m • K = 50 W m⁻¹ K⁻¹ • T_h = 100°C, T_c = 20°C → (T_h - T_c) = 80°C • t = 5 min = 5 × 60 = 300 s Formula: Q = KA(T_h - T_c)t / d Solution: Q = (50 × 2 × 80 × 300) / 0.02

Card 5Conduction

A cubical thermocol box (side 30 cm, thickness 5 cm, K = 0.01 J s⁻¹ m⁻¹ °C⁻¹) is full of ice. Outside temperature is 45°C. How much ice melts in 6 hours? (Latent heat of ice = 335 J g⁻¹)

Answer

Given: • Side = 30 cm = 0.30 m → Area of one face = 0.30 × 0.30 = 0.09 m² = 900 × 10⁻⁴ m² • d = 5 cm = 0.05 m • K = 0.01 J s⁻¹ m⁻¹ °C⁻¹ • T_h - T_c = 45 - 0 = 45°C • t = 6 h = 6 × 60 × 60 = 21600 s •

Card 6Conduction

Why do we wear woollen clothes in winter? Relate your answer to thermal conductivity.

Answer

Wool traps air between its fibres. Air has a very low thermal conductivity (K = 0.025 W m⁻¹ K⁻¹), making it an excellent insulator. Mechanism: 1. Warm air gets trapped between wool fibres. 2. Low K o

Card 7Convection

Explain the mechanism of convection with an example. Why does hot fluid rise?

Answer

Mechanism of Convection: 1. A fluid (liquid or gas) near a heat source gets heated. 2. It expands → its density decreases. 3. Due to reduced density, buoyant force pushes it upward. 4. Cooler, denser

Card 8Radiation

What is radiation? List four key properties of thermal radiation.

Answer

Definition: Radiation is the continuous emission of energy from the surface of a body in the form of electromagnetic waves, without requiring any medium. Key Properties: 1. Speed: Travels at speed of

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What are the important topics in Heat Transfer and Solar Energy for NIOS Class 12 Physics?
Key topics in Heat Transfer and Solar Energy include Heat Transfer and Solar Energy — Chapter Concept Map, Heat Transfer and Solar Energy — Complete Concept Map, Heat Transfer and Solar Energy — Complete Concept Map. These are the concepts NIOS Class 12 examiners draw on most — study them first, then practise related questions.
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Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
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There are 34 flashcards for Heat Transfer and Solar Energy covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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