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Electric Potential and Capacitors

NIOS · Class 12 · Physics

Flashcards for Electric Potential and Capacitors — NIOS Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

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Card 1Electric Potential

State the definition of Electric Potential at a point in an electric field.

Answer

Electric Potential at a point is defined as the work done against the electric force in moving a unit positive charge from infinity (outside the field) to that point. Formula: V = W / q₀ Key Points:

Card 2Potential Difference

A charge of 2 × 10⁻⁶ C is moved between two points in an electric field and 4 × 10⁻⁵ J of work is done. What is the potential difference between the two points?

Answer

Given: • Work done W = 4 × 10⁻⁵ J • Charge q₀ = 2 × 10⁻⁶ C Formula: V_AB = W_AB / q₀ Step 1: Substitute values V_AB = (4 × 10⁻⁵ J) / (2 × 10⁻⁶ C) Step 2: Calculate V_AB = 4/2 × 10⁻⁵⁺⁶ = 2 × 10¹ = 2

Card 3Electric Potential due to Point Charge

Derive the expression for electric potential at a point P at distance r from a point charge +q.

Answer

Setup: Point charge +q at O, point P at distance r from O. Derivation Steps: Step 1: Electric field at distance x from +q: E = (1/4πε₀) × (q/x²) Step 2: Work done in moving test charge q₀ from ∞ to

Card 4Electric Potential due to Point Charge

The electric potential at a point is 400 V and the electric field magnitude is 150 N/C. Find the distance x from the charge and the value of the charge q.

Answer

Given: • V = 400 V • E = 150 N/C Find: x and q Step 1: Use relation E = V/x (for point charge, valid near the charge) 150 = 400 / x x = 400/150 = 2.67 m Step 2: Use E = (1/4πε₀) × (q/x²) 150 = (9 ×

Card 5Electric Potential due to Dipole

Write the formula for electric potential due to an electric dipole at a point P(r, θ). What are its values on the axial and equatorial lines?

Answer

Dipole: charges −q at A and +q at B, separated by 2l, dipole moment p = q × 2l. General Formula: V = p cosθ / (4πε₀r²) Special Cases: 1. Axial line (side of +q), θ = 0°: cos0° = 1 V_axial = p / (4π

Card 6Equipotential Surfaces

What is an equipotential surface? State two important properties of equipotential surfaces.

Answer

Definition: An equipotential surface is a surface on which every point is at the same electric potential. Example: The equatorial plane of a dipole (V = 0 everywhere on it). Properties: 1. No work

Card 7Relation between E and V

What is the relation between Electric Field E and Electric Potential V? What does the negative sign indicate?

Answer

Relation: E = −ΔV / Δr In words: Electric field at a point = Negative rate of change of potential with distance (negative potential gradient) For uniform field: E = (V_A − V_B) / d Where d = separa

Card 8Relation between E and V

The potential difference between two parallel plates separated by 3 mm is 12.0 V. Calculate the electric field between the plates.

Answer

Given: • Potential difference V = 12.0 V • Separation d = 3 mm = 3 × 10⁻³ m Formula: E = V / d Step 1: Substitute values E = 12.0 V / (3 × 10⁻³ m) Step 2: Calculate E = 12.0 / 0.003 = 4000 V/m Ans

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What are the important topics in Electric Potential and Capacitors for NIOS Class 12 Physics?
Key topics in Electric Potential and Capacitors include Capacitor with Dielectric: Battery Connected vs Disconnected, Electric Potential and Capacitors — Complete Concept Map, Chapter Overview: Electric Potential and Capacitors. These are the concepts NIOS Class 12 examiners draw on most — study them first, then practise related questions.
How to score full marks in Electric Potential and Capacitors — NIOS Class 12 Physics?
Understand the core concepts first, then work through the 44 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
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There are 35 flashcards for Electric Potential and Capacitors covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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