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Work, Energy and Power

NIOS · Class 12 · Physics

Flashcards for Work, Energy and Power — NIOS Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions39 flashcards5 concepts

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An illustration showing a block being pulled by a constant force F at an angle theta to the horizontal displacement S, with the formula W = F ⋅ S = FS cosθ.
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39 Flashcards
Card 1Work

State the definition and formula for Work done by a constant force. What is its SI unit?

Answer

Work done by a constant force F acting at angle θ with displacement d is: W = F · d · cos θ In vector form: W = F⃗ · d⃗ Key Points: • Work is a SCALAR quantity • If θ = 0°, W = Fd (maximum positive

Card 2Work

A force of 6 N is applied on an object at 60° with the horizontal. The object moves 2 m horizontally. Calculate the work done.

Answer

Given: F = 6 N, θ = 60°, d = 2 m Find: Work done W Formula: W = F · d · cos θ Solution: W = 6 × 2 × cos 60° W = 6 × 2 × 0.5 W = 6 J Answer: W = 6 J Note: Only the horizontal component (F cos60° =

Card 3Work

Why is no work done when you push a wall with all your strength but it does not move?

Answer

Because Work = F × d × cos θ, and displacement d = 0. W = F × 0 × cos θ = 0 J Even if force applied is very large, ZERO displacement means ZERO work done in the scientific sense. Real-world example

Card 4Work

A force F⃗ = (2î + 3ĵ) N produces a displacement d⃗ = (–î + 2ĵ) m. Calculate the work done.

Answer

Given: F⃗ = (2î + 3ĵ) N d⃗ = (–î + 2ĵ) m Formula: W = F⃗ · d⃗ Solution (Dot Product): W = (2)(–1) + (3)(2) W = –2 + 6 W = 4 J Answer: W = 4 J Note: Even though one component contributes negative w

Card 5Work

When is work done by gravity POSITIVE and when is it NEGATIVE? Explain with examples.

Answer

Work done by Gravity = mg × displacement × cos θ CASE 1 – Object moving DOWNWARD: • Force (mg) ↓ and displacement ↓ → θ = 0° • W_gravity = +mgh (POSITIVE) • Example: A stone falling from a building

Card 6Work Done by Variable Force

State Hooke's Law for a spring. Write the formula for work done in compressing or stretching a spring by distance x.

Answer

Hooke's Law: The restoring force in a spring is proportional to the displacement from equilibrium: F_s = –kx Where: • k = spring constant (N/m) • x = compression or extension (m) • Negative sign sho

Card 7Work Done by Variable Force

A mass of 2 kg is attached to a spring of force constant k = 100 N/m. Calculate the work done by an external force in stretching the spring by 10 cm.

Answer

Given: m = 2 kg, k = 100 N/m, x = 10 cm = 0.1 m Find: Work done W Formula: W = ½ k x² Solution: W = ½ × 100 × (0.1)² W = ½ × 100 × 0.01 W = 50 × 0.01 W = 0.5 J Answer: W = 0.5 J Note: Work done b

Card 8Power

Define Power. Write its formula, SI unit, and dimensional formula. How is kilowatt-hour (kWh) related to joules?

Answer

Power is the RATE of doing work. Average Power: P = W / t Instantaneous Power: P = dW/dt SI Unit: Watt (W) = Joule/second = J s⁻¹ Dimensional Formula: [ML²T⁻³] Other Units: • 1 kW = 10³ W • 1 MW

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Frequently Asked Questions

What are the important topics in Work, Energy and Power for NIOS Class 12 Physics?
Key topics in Work, Energy and Power include Work, Energy and Power — Complete Concept Map, How to Correctly Calculate Work Done — Step by Step, Work, Energy and Power - Full Chapter Mind Map. These are the concepts NIOS Class 12 examiners draw on most — study them first, then practise related questions.
How to score full marks in Work, Energy and Power — NIOS Class 12 Physics?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Work, Energy and Power?
There are 39 flashcards for Work, Energy and Power covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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