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Electric Current

NIOS · Class 12 · Physics

Flashcards for Electric Current — NIOS Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions35 flashcards5 concepts

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Graphs showing the variation of resistivity with temperature for different types of materials: metals, semiconductors, and alloys.
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35 Flashcards
Card 1Electric Current

Define electric current. Write its SI unit and formula.

Answer

Electric current is the rate of flow of electric charge through a cross-sectional area placed perpendicular to the direction of flow. Formula: I = ΔQ / Δt For instantaneous current: I = dq/dt SI Uni

Card 2Electric Current

6.0 × 10¹⁶ electrons pass through any cross-section of a wire per second. Find the current in the wire.

Answer

Given: Number of electrons per second, n = 6.0 × 10¹⁶ Charge on electron, e = 1.6 × 10⁻¹⁹ C Time, Δt = 1 s Step 1: Find total charge ΔQ = n × e = 6.0 × 10¹⁶ × 1.6 × 10⁻¹⁹ ΔQ = 9.6 × 10⁻³ C Step 2: C

Card 3Ohm's Law

State Ohm's Law. Write its mathematical form and state its limitations.

Answer

Ohm's Law: The electric current through a conductor is directly proportional to the potential difference across it, provided physical conditions (temperature, pressure) remain unchanged. Mathematical

Card 4Ohm's Law

A 220V electricity supply powers a bulb drawing 0.2A current. Find the resistance of the bulb.

Answer

Given: V = 220 V I = 0.2 A Formula: R = V / I (Ohm's Law) Step 1: Apply formula R = 220 / 0.2 Answer: R = 1100 Ω Real-world context: This is similar to a standard home bulb connected to a 220V su

Card 5Resistance and Resistivity

What is resistivity? Give its formula, unit, and explain how it differs from resistance.

Answer

Resistivity (ρ): A property of the material of a conductor. It is the resistance offered by a wire of 1 metre length and 1 m² area of cross-section. Formula: R = ρ × (l / A) Therefore: ρ = RA / l Un

Card 6Resistance and Resistivity

A conducting wire is 60 m long with radius 0.5 cm. A potential difference of 5.0 V produces a current of 2.5 A. Calculate the resistivity of the wire.

Answer

Given: l = 60.0 m Radius r = 0.5 cm = 5.0 × 10⁻³ m V = 5.0 V I = 2.5 A Step 1: Find Resistance R = V/I = 5.0/2.5 = 2.0 Ω Step 2: Find Area of Cross-Section A = πr² = 3.14 × (5.0 × 10⁻³)² A = 3.14 ×

Card 7Resistance and Resistivity

Two copper wires A and B have the same length. Diameter of A is twice that of B. Compare their resistances.

Answer

Given: lₐ = l_b = l (same length) d_A = 2 d_B → rₐ = 2r_b Formula: R = ρl / A = ρl / (πr²) Step 1: Rₐ = ρl / (πrₐ²) R_B = ρl / (πr_b²) Step 2: Take ratio Rₐ / R_B = r_b² / rₐ² Step 3: Substitute

Card 8Grouping of Resistors

What is the equivalent resistance when resistors R₁, R₂, R₃ are connected in SERIES? Explain with the key property of series circuits.

Answer

Series Combination: R_eq = R₁ + R₂ + R₃ + ... Key Properties: 1. Same current (I) flows through all resistors 2. Voltage divides: V = V₁ + V₂ + V₃ where V₁ = IR₁, V₂ = IR₂, V₃ = IR₃ 3. Equivalent

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What are the important topics in Electric Current for NIOS Class 12 Physics?
Key topics in Electric Current include Electric Current - Full Chapter Concept Map, Electric Current — Complete Chapter Mind Map, Electric Current – Chapter Overview Mind Map. These are the concepts NIOS Class 12 examiners draw on most — study them first, then practise related questions.
How to score full marks in Electric Current — NIOS Class 12 Physics?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Electric Current?
There are 35 flashcards for Electric Current covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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