Motion in a Plane
NIOS · Class 12 · Physics
Flashcards for Motion in a Plane — NIOS Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.
Interactive on Super Tutor
Studying Motion in a Plane? Get the full interactive chapter.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for flashcards and more.
1,000+ Class 12 students started this chapter today
Learn better with visuals Super Tutor has hundreds of illustrations like this across every chapter — all free to try.
Get startedWhat is projectile motion? State its two key properties.
Answer
Projectile motion is the motion of an object launched into the air that moves under the influence of gravity alone (ignoring air resistance). Two key properties: 1. Constant horizontal velocity compo…
A projectile is launched with initial velocity v₀ = 20 m/s at angle θ₀ = 30° to the horizontal. Find its horizontal and vertical components of initial velocity.
Answer
Given: v₀ = 20 m/s, θ₀ = 30° Formulas: • Horizontal component: v₀ₓ = v₀ cos θ₀ • Vertical component: v₀ᵧ = v₀ sin θ₀ Solution: • v₀ₓ = 20 × cos 30° = 20 × (√3/2) = 10√3 ≈ 17.32 m/s • v₀ᵧ = 20 × sin …
State the formula for maximum height of a projectile. What condition must be satisfied at maximum height?
Answer
At maximum height, the vertical component of velocity becomes ZERO (vy = 0). Formula for Maximum Height: h = v₀² sin²θ₀ / (2g) Where: • v₀ = initial speed (m/s) • θ₀ = angle of projection • g = 9.8…
A ball is projected with initial speed 30 m/s at 45°. Calculate the maximum height reached. (Take g = 10 m/s²)
Answer
Given: v₀ = 30 m/s, θ₀ = 45°, g = 10 m/s² Find: Maximum height h Formula: h = v₀² sin²θ₀ / (2g) Step 1: sin 45° = 1/√2, so sin²45° = 1/2 Step 2: h = (30)² × (1/2) / (2 × 10) Step 3: h = 900 × 0.5 / …
State the formula for Time of Flight of a projectile. What does it represent?
Answer
Time of Flight is the total time the projectile remains in the air — from launch to landing. Formula: T = 2v₀ sin θ₀ / g Where: • v₀ = initial speed (m/s) • θ₀ = angle of projection • g = 9.8 m/s² •…
A projectile is launched at 60° with initial speed 40 m/s. Find the time of flight. (g = 10 m/s²)
Answer
Given: v₀ = 40 m/s, θ₀ = 60°, g = 10 m/s² Find: Time of Flight T Formula: T = 2v₀ sin θ₀ / g Step 1: sin 60° = √3/2 ≈ 0.866 Step 2: T = 2 × 40 × 0.866 / 10 Step 3: T = 69.28 / 10 Step 4: T = 6.93 s …
State the formula for Horizontal Range of a projectile. At what angle is the range maximum?
Answer
Range is the horizontal distance covered by the projectile. Formula: R = v₀² sin 2θ₀ / g Where: • v₀ = initial speed (m/s) • θ₀ = angle of projection • g = 9.8 m/s² • R is in metres (m) Maximum Ran…
A hammer is thrown with initial speed 14 m/s at 45°. Calculate the range. (g = 9.8 m/s²)
Answer
Given: v₀ = 14 m/s, θ₀ = 45°, g = 9.8 m/s² Find: Range R Formula: R = v₀² sin 2θ₀ / g Step 1: sin 2(45°) = sin 90° = 1 Step 2: R = (14)² × 1 / 9.8 Step 3: R = 196 / 9.8 Step 4: R = 20 m Answer: Ran…
+22 more flashcards available
Practice AllFrequently Asked Questions
What are the important topics in Motion in a Plane for NIOS Class 12 Physics?
How to score full marks in Motion in a Plane — NIOS Class 12 Physics?
How many flashcards are available for Motion in a Plane?
Sources & Official References
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
More resources for Motion in a Plane
Important Questions
Practice with board exam-style questions
Syllabus
What topics to cover
Revision Notes
Key points for last-minute revision
Study Plan
Step-by-step plan to ace this chapter
Formula Sheet
All formulas in one place
Chapter Summary
Understand the chapter at a glance
Practice Quiz
Test yourself with a quick quiz
Concept Maps
See how topics connect visually
NCERT Solutions
Every textbook question solved step by step
For serious students
Get the full Motion in a Plane chapter — for free.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan for NIOS Class 12 Physics.