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Periodic Classification of Elements

NIOS · Class 10 · Science & Tech

Flashcards for Periodic Classification of Elements — NIOS Class 10 Science & Tech. Quick Q&A cards covering key concepts, definitions, and formulas.

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An illustration showing a well-organized chemist's shop with medicines classified and arranged, contrasting it with a disorganized one, to explain the need for classifying elements.
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40 Flashcards
Card 1Early classification of elements

What was the earliest classification of elements?

Answer

The earliest classification of elements was into metals and non-metals. This helped in grouping elements with similar general properties.

Card 2Need for classification

Why was classification of elements needed by the middle of the nineteenth century?

Answer

Nearly 60 elements were known by then, and their compounds were also very large in number. It became difficult to study each element separately, so classification helped in systematic study.

Card 3Basis for classification

How did William Prout's work help in classification of elements?

Answer

William Prout's work in 1815 showed that the atomic mass of an element remains constant. This made atomic mass a useful basis for classification.

Card 4Dobereiner's triads

What is Dobereiner's law of triads?

Answer

When elements are arranged in order of increasing atomic mass, the atomic mass of the middle element is nearly equal to the arithmetic mean of the other two, and its properties are intermediate betwee

Card 5Dobereiner's triads

Work out the Dobereiner triad mean for lithium, sodium and potassium.

Answer

Atomic masses: lithium = 7 u, potassium = 39 u. Mean = (7 + 39) / 2 = 23 u. Sodium has atomic mass 23 u, so the triad fits the rule.

Card 6Dobereiner's triads

Work out the Dobereiner triad mean for calcium, strontium and barium.

Answer

Atomic masses: calcium = 40 u, barium = 137 u. Mean = (40 + 137) / 2 = 88.5 u. Strontium has atomic mass about 88 u, so the triad fits the rule.

Card 7Dobereiner's triads

Work out the Dobereiner triad mean for chlorine, bromine and iodine.

Answer

Atomic masses: chlorine = 35.5 u, iodine = 127 u. Mean = (35.5 + 127) / 2 = 81.25 u. Bromine has atomic mass about 80 u, so the triad fits the rule.

Card 8Dobereiner's triads

Why did Dobereiner's triads not become a complete classification system?

Answer

Only a few elements could be arranged into triads. So, the system was useful but limited.

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What are the important topics in Periodic Classification of Elements for NIOS Class 10 Science & Tech?
Key topics in Periodic Classification of Elements include Periodic Classification Development Overview, Periodic Classification Overview, Periodic Classification Overview. These are the concepts NIOS Class 10 examiners draw on most — study them first, then practise related questions.
How to score full marks in Periodic Classification of Elements — NIOS Class 10 Science & Tech?
Understand the core concepts first, then work through the 44 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
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