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Periodic Classification of Elements — Flashcards

NIOS · Class 10 · Science & Tech

40 flashcards for Periodic Classification of Elements (NIOS Class 10 Science & Tech) to test yourself on key terms and facts.

44 questions40 flashcards4 formulas & key relations5 concepts

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An illustration showing a well-organized chemist's shop with medicines classified and arranged, contrasting it with a disorganized one, to explain the need for classifying elements.
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40 Flashcards·
Early classification of elementsNeed for classificationBasis for classificationDobereiner's triads
Card 1Early classification of elements

What was the earliest classification of elements?

Answer

The earliest classification of elements was into metals and non-metals. This helped in grouping elements with similar general properties.

Card 2Need for classification

Why was classification of elements needed by the middle of the nineteenth century?

Answer

Nearly 60 elements were known by then, and their compounds were also very large in number. It became difficult to study each element separately, so classification helped in systematic study.

Card 3Basis for classification

How did William Prout's work help in classification of elements?

Answer

William Prout's work in 1815 showed that the atomic mass of an element remains constant. This made atomic mass a useful basis for classification.

Card 4Dobereiner's triads

What is Dobereiner's law of triads?

Answer

When elements are arranged in order of increasing atomic mass, the atomic mass of the middle element is nearly equal to the arithmetic mean of the other two, and its properties are intermediate betwee…

Card 5Dobereiner's triads

Work out the Dobereiner triad mean for lithium, sodium and potassium.

Answer

Atomic masses: lithium = 7 u, potassium = 39 u. Mean = (7 + 39) / 2 = 23 u. Sodium has atomic mass 23 u, so the triad fits the rule.

Card 6Dobereiner's triads

Work out the Dobereiner triad mean for calcium, strontium and barium.

Answer

Atomic masses: calcium = 40 u, barium = 137 u. Mean = (40 + 137) / 2 = 88.5 u. Strontium has atomic mass about 88 u, so the triad fits the rule.

Card 7Dobereiner's triads

Work out the Dobereiner triad mean for chlorine, bromine and iodine.

Answer

Atomic masses: chlorine = 35.5 u, iodine = 127 u. Mean = (35.5 + 127) / 2 = 81.25 u. Bromine has atomic mass about 80 u, so the triad fits the rule.

Card 8Dobereiner's triads

Why did Dobereiner's triads not become a complete classification system?

Answer

Only a few elements could be arranged into triads. So, the system was useful but limited.

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Frequently Asked Questions

What are the important topics in Periodic Classification of Elements for NIOS Class 10 Science & Tech?
Key topics in Periodic Classification of Elements include Development of Classification of Elements, Dobereiner’s Triads, Newlands’ Law of Octaves, Mendeleev’s Periodic Law and Periodic Table. Study these first, then practise questions on each for the NIOS Class 10 board exam.
How many flashcards are available for Periodic Classification of Elements?
There are 40 flashcards for Periodic Classification of Elements covering key definitions, facts and ideas. A few sample cards are shown on this page.
How should I revise Periodic Classification of Elements for the NIOS Class 10 board exam?
Learn the core ideas first, then work through the 44 practice questions on Periodic Classification of Elements. Revise definitions regularly and use flashcards for quick recall before the exam.

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