Periodic Classification of Elements — Flashcards
NIOS · Class 10 · Science & Tech
40 flashcards for Periodic Classification of Elements (NIOS Class 10 Science & Tech) to test yourself on key terms and facts.
Interactive on Super Tutor
Studying Periodic Classification of Elements? Get the full interactive chapter.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for flashcards and more.
Free trial, no card needed.

One of 15 illustrations for Periodic Classification of Elements in Super Tutor — alongside flashcards, concept maps and practice questions.
What was the earliest classification of elements?
Answer
The earliest classification of elements was into metals and non-metals. This helped in grouping elements with similar general properties.
Why was classification of elements needed by the middle of the nineteenth century?
Answer
Nearly 60 elements were known by then, and their compounds were also very large in number. It became difficult to study each element separately, so classification helped in systematic study.
How did William Prout's work help in classification of elements?
Answer
William Prout's work in 1815 showed that the atomic mass of an element remains constant. This made atomic mass a useful basis for classification.
What is Dobereiner's law of triads?
Answer
When elements are arranged in order of increasing atomic mass, the atomic mass of the middle element is nearly equal to the arithmetic mean of the other two, and its properties are intermediate betwee…
Work out the Dobereiner triad mean for lithium, sodium and potassium.
Answer
Atomic masses: lithium = 7 u, potassium = 39 u. Mean = (7 + 39) / 2 = 23 u. Sodium has atomic mass 23 u, so the triad fits the rule.
Work out the Dobereiner triad mean for calcium, strontium and barium.
Answer
Atomic masses: calcium = 40 u, barium = 137 u. Mean = (40 + 137) / 2 = 88.5 u. Strontium has atomic mass about 88 u, so the triad fits the rule.
Work out the Dobereiner triad mean for chlorine, bromine and iodine.
Answer
Atomic masses: chlorine = 35.5 u, iodine = 127 u. Mean = (35.5 + 127) / 2 = 81.25 u. Bromine has atomic mass about 80 u, so the triad fits the rule.
Why did Dobereiner's triads not become a complete classification system?
Answer
Only a few elements could be arranged into triads. So, the system was useful but limited.
+32 more flashcards
Practise AllFrequently Asked Questions
What are the important topics in Periodic Classification of Elements for NIOS Class 10 Science & Tech?
How many flashcards are available for Periodic Classification of Elements?
How should I revise Periodic Classification of Elements for the NIOS Class 10 board exam?
Sources & Official References
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
More resources for Periodic Classification of Elements
Practice Quiz
Test yourself with a quick quiz
Important Questions
Exam-style questions with answers
Revision Notes
Key points for last-minute revision
Formula Sheet
The chapter's formulas in one place
Chapter Summary
Understand the chapter at a glance
Concept Maps
See how topics connect
Study Plan
Step-by-step plan for this chapter
Syllabus
What topics to cover
For serious students
Get the full Periodic Classification of Elements chapter — start free.
Quizzes, flashcards, an AI doubt solver and a study plan for NIOS Class 10 Science & Tech. Free to start, no card needed.